Answer:
Triangle ΔPYX is congruent to triangle ΔYQZ by Angle-Angle-Side condition of congruency
Step-by-step explanation:
The given
Statement [tex]{}[/tex] Reason
PQR is a triangle [tex]{}[/tex] Given
XYZR is a parallelogram [tex]{}[/tex] Given
X is the midpoint of RP [tex]{}[/tex] Given
Y is the midpoint of PQ [tex]{}[/tex] Given
Z is the midpoint of QR [tex]{}[/tex] Given
Therefore;
QY = YP, Definition of midpoint
XY is parallel to QR, and YZ is parallel to RP Midpoint theorem
Therefore, ∠PYX ≅ ∠PQR and ∠QZY ≅ ∠YXP Corresponding angles of parallel lines
From which we have;
Triangle ΔPYX is congruent to triangle ΔYQZ by Angle-Angle-Side condition of congruency.