Respuesta :
Answer:
62.6 %
Explanation:
Pb(NO₃)₂ = 207 + 124 = 331 gram
331 gram of lead nitrate contains 207 grams of lead
100 gram of lead nitrate contains
207 x 100 / 331 = 62.6 %
It can be deduced that percentage by mass of lead in Pb(NO₃)₂ is B. 62.6%.
How to calculate the percentage?
From the given information, Pb(NO₃)₂ = 207 + 124 = 331 grams.
Therefore, 331 gram of lead nitrate contains 207 grams of lead. It can be deduced that 100 gram of lead nitrate will contain:
= 207 x 100 / 331
= 62.6 %
In conclusion, the correct option is 62.6%.
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