Answer:
0.5
Step-by-step explanation:
Given that: An average concentration of 1 coliform bacteria per 20 cc of the river water.
This implies that in 20 cc of the water, it is certain that 1 coliform bacteria would be found. So that:
pr(1 bacteria in 20 cc of water) = 1
i.e the probability of getting 1 bacteria in 20 cc of water is 1.
The probability of the 10 cc sample of water containing 2 coliform bacteria can be determined as:
pr(2 bacteria in 10 cc of water) = [tex]\frac{1}{2}[/tex]
= 0.5