Answer:
D
Step-by-step explanation:
Consider one of the circles
the area (A) of the sector is calculated as
A = area of circle × fraction of circle
Since ΔHPU is equilateral then ∠HPU = 60°, thus
A = πr² × [tex]\frac{60}{360}[/tex]
= π × 3² × [tex]\frac{1}{6}[/tex]
= 9π × [tex]\frac{1}{6}[/tex] = [tex]\frac{3}{2}[/tex] π
Shaded area = area of circle - area of sector = 9π - [tex]\frac{3}{2}[/tex] π = [tex]\frac{15}{2}[/tex] π
Since both circles are congruent then
total shaded area = 2 × [tex]\frac{15}{2}[/tex] π = 15π → D
