Answer:
The radius is [tex]r = 3.21*10^{4} \ m[/tex]
Explanation:
From the question we are told that
The density is [tex]\rho = 2000 \ kg/m^3[/tex]
The speed is [tex]v = 24 \ m/s[/tex]
Generally the largest radius of the asteroid is mathematically represented as
[tex]r = \frac{v^2}{ \sqrt{G * \rho * [\frac{4}{3} ] * \pi} }[/tex]
=> [tex]r = \frac{24^2}{ \sqrt{ 6.67*10^{-11} * 2000 * [\frac{4}{3} ] *3.142 } }[/tex]
=> [tex]r = 3.21*10^{4} \ m[/tex]