Answer:
[tex]yes \: she \: is \: right. \\ she \: could \: had \: saved \: 3,244.65 \\ had \: it \: been \: she \: sent \: all \: her \: parcels \: by \: parcel \: r \: go.[/tex]
Step-by-step explanation:
[tex]let \: less \: than \: 2kg \: be : x \\ let \:2kg \: less \: than \: 5kg \: be : y\\ let \:5kg \: to \: 10kg \: be : z \\ then \: x \: y \: z \: has \: the \: following \: values : \\number \: of \: x \: acquired \: = 23 + 21 = 44. \\number \: of \: y \: acquired \: = 28 + 27 = 55. \\number \: of \: z \: acquired \: = 19 + 32 = 51. \\ \\ \boxed{with \: parcel \: express} \\the \: cost\: value \: of \: x = 44 \times 3.8 = 167.2\\the \: cost\: value \: of \: y= 55 \times 5.99 = 329.45\\the \: cost\: value \: of \: z= 51 \times 71.4 = 3,646.5 \\ \\ therefore \: the \: total \: number \: of \: items \: purchased : = x + y + z = 44 + 55 + 51 = 150. \\ and \: the \: total \: cost : = 167.2 + 329.45 + 3,646.5 = 4,143.15 \\ \\ \boxed{with \: parcel \: r \: go} \\the \: total \: value\: is : =x + y + z = (0 - 15kg) = 150 \\ the \: total \: cost \: is : = 150 \times 5.99 = 898.5 \\ therefore \: she \: is \: right.[/tex]
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