Question

What is the frequency of a radar photon with energy 6.80 x 10^-25J? (h = 6.63 x 10^-34 J•s)

Answer 1

Answer:

E=hv where E=energy h=planks constant v=frequency

So, v=E/h

       =6.8x10^-25/6.63x10^-34

       =1025641026Hz

       =1.03x10^9Hz

       =1.03GHz

Explanation:

Answer 2

The frequency of radar photon is "1.03 GHz".

According to the question,

Energy,

• E = $6.80\times 10^{-25} \ J$

Planks constant,

• h = $6.63\times 10^{-34} \ J.s$

The frequency will be:

→ $v = \frac{E}{h}$

     $= \frac{6.80\times 10^{-25} \ J}{6.63\times 10^{-34} \ J.s}$

     $= 1.03\times 10^{9\ Hz}$

     $= 1.03 \ GHz$

Thus the above response is right.

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