Question

When calcium nitrate, Ca(NO3)2, dissolves in water, it dissociates into its ions. We can represent that process by the following equation: Ca(NO3)2(s) → Ca2+(aq) + 2NO3-(aq) When 1.5 mol calcium nitrate dissolves in water, how many moles of ions should be present in solution? Group of answer choices

Answer 1

Answer:

4.5 moles

Explanation:

The given reaction is

$Ca(NO_3)_2(s)\rightarrow Ca^{+2}(aq)+2NO_3^-(aq)$

Moles of calcium nitrate is 1.5

$Ca(NO_3)_2$ produces 2 moles of $Ca^{+2}$ and 1 mole of $2NO_3^-$

So the total moles of the ions of the products are 3

Therefore in the solution the moles of ions present are

$3\times1.5=4.5\ \text{moles}$

Moles of ions present in solution is 4.5.