Answer:
rotor slip = 10.42 %
Frequency = Â 6.24hz
Explanation:
given data
synchronous speed = 1200 RPM
rotor rotating speed = 1075 RPM
solution
first we get here rotor slip that is
rotor slip = ( synchronous speed - rotor rotating speed  ) ÷ synchronous speed  .............................1
rotor slip = [tex]\frac{1200 -1075}{1200}[/tex]
rotor slip = 0.10416 Â
rotor slip = 10.42 %
and
frequency of the induced rotor voltage is
Frequency = rotor slip × 60
Frequency = 10.42 %  × 60
Frequency = Â 6.24hz