Question

-25 Points-
If P= (-2,-1) and Q= (-6,-3) are the endpoints of the diameter of a circle, find the equation of the circle.

Answer 1

Answer:

(x+4)^2+(y+2)^2=5

or

(x-(-4))^2+(y-(-2))^2=5

Step-by-step explanation:

Format for an equation of a circle: (x-h)^2+(y-k)^2=r^2

Center: (1/2*(-6-2),1/2*(-3-1))=(-4,-2)

Radius: sqrt(20)/2 or sqrt(5)

So, it's

(x+4)^2+(y+2)^2=5

or

(x-(-4))^2+(y-(-2))^2=5

Answer 2

Answer:

-4 , -2 , 5

Step-by-step explanation:

(x-(-4))^2+(y-(-2))^2=5

since 2 negatives equal a positive, - -4 = +4

same thing for -2

(x+4)^2+(y+2)^2=5