can someone help me?

Exterior angle = Sum of its interior opposite angles ( exterior angle property )
Which means :-
[tex]7x - 1 + 63 = 14x - 8[/tex]
[tex]7x + ( - 1) + 63 = 14x - 8[/tex]
[tex]7x + 62 = 14x - 8[/tex]
[tex]7x + 62 - 14x = ( - 8)[/tex]
[tex]- 7x + 62 = ( - 8)[/tex]
[tex]- 7x = - 8 - 62[/tex]
[tex] - 7x = ( - 70)[/tex]
[tex]x = \frac{ - 70}{ - 7} [/tex]
[tex]\color{hotpink} x = 10 [/tex]
Then :-
1) ∠ 7x - 1
= 7 × 10 - 1
= 70 - 1
2) ∠14x - 8
= 14 × 10 - 8
= 140 - 8
As the sum of interior opposite angles of this triangle is equivalent to the value of the exterior angle (69+63=132), we can conclude that we have found out the correct value of x .
Therefore , the value of x = 10 .