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We know that polar molecules' attraction is stronger than that of non polar ones; this can be a good basis for us to check the substances' polarity. Knowing that polar forces are stronger, we can eliminate all options referring to them as being the weaker force; that is, options C and A. Next, we know that stronger forces will result in lower volatility so we can eliminate option D. The answer is B, assuming the compound has an odor.
We know that polar molecules' attraction is stronger than that of non polar ones; this can be a good basis for us to check the substances' polarity. Knowing that polar forces are stronger, we can eliminate all options referring to them as being the weaker force; that is, options C and A. Next, we know that stronger forces will result in lower volatility so we can eliminate option D. The answer is B, assuming the compound has an odor.
The answer is,
B. Test for an odor. The nonpolar substance should have a higher volatility and stronger odor because of its London dispersion forces.
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