Question

pete's dad usually deposits $25 into his bank account every week. for the next 8 weeks , he wants to deposit more than the usual $25, and he wants the extra amount deposited to be the same each week. which inequality and solution show how much more he can deposit each week and keep the total of his deposit above 500 for those 8 weeks? 8(25+x)>500;x>$300
25+8x>500;x>$59.37
8(25+x)>500;x>37.50
8(25)+x>500;x>$300

Answer 1

Answer:

$8(25+x)>500;x>37.5$

Step-by-step explanation:

Given : For the next 8 weeks , he wants to deposit more than the usual $25.

To Find: He wants the extra amount deposited to be the same each week. which inequality and solution show how much more he can deposit each week and keep the total of his deposit above 500 for those 8 weeks.

Solution:

His usual deposit = $25

He wants the extra amount deposited to be the same each week.

Let x be the extra amount.

So, Amount need to be deposited per week = 25+x

Amount need to be deposited 8 weeks = 8(25+x)

Now we are given that he total of his deposit should be above 500.

So, $8(25+x)>500$

$200+8x>500$

$8x>300$

$x>\frac{300}{8}$

$x>37.5$

So, inequality : $8(25+x)>500$

Solution:  $x>37.5$

Thus Option C is correct.

Hence , the inequality and solution which shows how much more he can deposit each week and keep the total of his deposit above 500 for those 8 weeks is $8(25+x)>500;x>37.5$