Question

Determine the remainder when (x3 – 5x2 14x – 5) is divided by (x 3)

Answer 1

Hello,

P(x)=x^3-5x^2+14x-5

P(-3)=(-3)^3-5*(-3)²+14*(-3)-5=-119
Remainder=-119

Answer 2

Answer:

The remainder is -119

Step-by-step explanation:

$(x^3 - 5x^2+ 14x - 5)$ divide by (x+3)

we use the remainder theorem to find the remainder

We are given with x+3

$x+3=0, x=-3$

To find remainder, we substitute -3 for x

$(x^3 - 5x^2+ 14x - 5)$

$((-3)^3 - 5(-3)^2+ 14(-3) - 5)$

$-27-45-42-5=-119$

The remainder is -119