Question

A bag contains 5 blue coins and 7 red coins. A coin is removed at random and replaced by three of the
other color.
Part 1 out of 3
What is the probability that the removed coin is blue? Enter your answer as a simplified fraction.
The probability that the removed coin is blue is

Answer 1

Answer:

The probability that the removed coin is blue is $\frac{5}{12}$.

Step-by-step explanation:

5 out of 12 coins are blue, so $\frac{5}{12}$ of the coins are blue. $\frac{5}{12} =0.4166666...$, so the probability that the removed coin is blue is about 42%. But $\frac{5}{12}$ is already simplified, so the answer as a simplified fraction is $\frac{5}{12}$. Hope this helps!

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