Respuesta :

assuming that 'Z' is a circle

perimiter=circumference=2pir
area=pir^2

p=5=c
5=2pir
divide both sides by 2pi
[tex] \frac{2.5}{pi} [/tex]=r

area=pir^2
area=pi[tex] (\frac{2.5}{pi})^2 [/tex]
area=2.5pi

area=2.5pi in^2
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