The average rate of change of the function over the interval 2 < x < 10 is 5
The function is given as:
h(x) = x^2 - 7x + 8
Calculate h(2) and h(10)
h(2) = 2^2 - 7 * 2 + 8
h(2) = -2
h(10) = 10^2 - 7 * 10 + 8
h(10) = 38
The average rate is then calculated as:
Rate = (h(10) - h(2))/(10 - 2)
This gives
Rate = (38 + 2)/(10 - 2)
Evaluate
Rate = 5
Hence, the average rate of change of the function over the interval 2 < x < 10 is 5
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