Respuesta :
Answer: The area of the circle will be eleven-fourteenth of the area of square.
Step-by-step explanation: Given that a square has a side of length 7 cm and a circle has a diameter of 7 cm. We need to find the statement which is true about the areas of these two figures.
The area of the square will be
[tex]S_a=7^2=49~\textup{cm}^2.[/tex]
And, the area of the circle will be
[tex]C_a=\pi r^2=\pi \times \left(\dfrac{7}{2}\right)^2=\dfrac{\pi}{4}\times 49=\dfrac{22}{7\times 4}\times 49\\\\\Rightarrow C_a=\dfrac{11}{14}\times S_a.[/tex]
Thus, the area of the circle will be eleven-fourteenth of the areq of the square.
Answer:
Area of Square having side length equal to 7cm
=(7)²
=49 cm²
because ,Area of square=Side × Side
⇒Area of Circle having diameter 7 cm will be
[tex]\text{radius}=\frac{\text{Diameter}}{2}\\\\\text{Area of circle}=\pi \times r^2\\\\=\frac{22}{7}\times (\frac{7}{2})^2\\\\=\frac{22\times 49}{7\times 4}\\\\=\frac{77}{2}\\\\=38.5 \text{cm}^2[/tex]
Area of square is larger than Area of circle by
=49-38.5
=10.5 cm²
