Question

PLEASE HELP!!!
what was the volume of air that has a volume of 6.00L at 120870 Pa, if the original pressure was 250020 Pa?

Answer 1

Answer:

The answer is 2.90 L

Explanation:

In order to find the original pressure , we use the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original volume

$V_1 = \frac{P_2V_2}{P_1}$

From the question

P1 = 250020 Pa

P2 = 120870 Pa

V2 = 6 L

We have

$V_1 = \frac{120870 \times 6}{250020} = \frac{725220}{250020} \\ = 2.90064794...$

We have the final answer as

2.90 L

Hope this helps you