Respuesta :
Answer:
[tex]\displaystyle 4.\overline{15} = \frac{137}{33}[/tex].
Step-by-step explanation:
Start by separating this decimal number into its integer part and its fraction part:
[tex]4.151515\cdots = 4 + 0.151515\cdots[/tex]
The most challenging task here is to express [tex]0.151515\cdots[/tex] as a proper fraction. Once that fraction is found, expressing the original number [tex]4.151515\cdots[/tex] will be as simple as rewriting a mixed number as an improper fraction.
Let [tex]x = 0.151515\cdots[/tex]. [tex](x + 4)[/tex] would then represent the original number.
Note that the repeating digits appear in groups of two. Therefore, if the digits in [tex]x[/tex] are shifted to the left by two places, the repeating part will continue to match:
[tex]\begin{aligned}x = 0.&151515\cdots && \\ 100\, x = 15.& 151515\cdots \end{aligned}[/tex].
Note, that this "shifting" is as simple as multiplying the initial number by [tex]100[/tex] (same as [tex]10[/tex] raised to the power of the number of digits that needs to be shifted.)
Subtract the original number from the shifted number to eliminate the fraction part completely:
[tex]\begin{aligned}&(100\, x) - x \\ &= 15.151515\cdots\\ & \phantom{=}- 0.151515\cdots\\&=15 \end{aligned}[/tex].
In other words:
[tex]99\, x = 15[/tex].
[tex]\displaystyle x = \frac{15}{99} = \frac{5}{33}[/tex].
Therefore, the original number would be:
[tex]\displaystyle x + 4 = \frac{5}{33} = \frac{132 + 5}{33} = \frac{137}{33}[/tex].