Respuesta :

option A

If any base has a power in fraction , then the denominator turns out to be the "n"th root of thw base & the numerator turns out to be the overall power.

Here

[tex] {64}^{ \frac{2}{3} } [/tex]

has 2/3 as power. So 3 turns out to be the 3rd root of 64 & 2 becomes the overall power. Hence

[tex] {64}^{ \frac{2}{3} } = {( \sqrt[3]{64} )}^{2} [/tex]

option A

If any base has a power in fraction , then the denominator turns out to be the "n"th root of thw base & the numerator turns out to be the overall power.

Here

has 2/3 as power. So 3 turns out to be the 3rd root of 64 & 2 becomes the overall power. Hence

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