max points+brainliest i guess answer fast doe bro im sped

option A
If any base has a power in fraction , then the denominator turns out to be the "n"th root of thw base & the numerator turns out to be the overall power.
Here
[tex] {64}^{ \frac{2}{3} } [/tex]
has 2/3 as power. So 3 turns out to be the 3rd root of 64 & 2 becomes the overall power. Hence
[tex] {64}^{ \frac{2}{3} } = {( \sqrt[3]{64} )}^{2} [/tex]
option A
If any base has a power in fraction , then the denominator turns out to be the "n"th root of thw base & the numerator turns out to be the overall power.
Here
has 2/3 as power. So 3 turns out to be the 3rd root of 64 & 2 becomes the overall power. Hence