Question

As the earth rotates through one revolution, a person standing on the equator traces out a circular path whose radius is equal to the radius of the earth (6.38×10^6). What is the average speed of this person in meters per second? If we are standing in latitude 43° north what is our average speed?

Answer 1

Answer:

The average speed will be "1038 mph".

Explanation:

Period for one revolution is:

T = 24 hours

  = 86,400 sec

x = c = 2πr

The given values is:

r = 6.38×10⁶ m

Now,

⇒  $T=\frac{2 \pi r}{v}$

Or,

⇒  $v=\frac{2 \pi r}{T}$

On substituting the values, we get

       $=\frac{2 \pi (6.38\times 10^6)}{86,400}$

       $=464 \ min/sec$

       $=(464 \frac{min}{sec}) (\frac{3600 \ sec}{1 \ hour} )(\frac{1 \ mi}{1609 \ m} )$

       $=1038 \ mph$