Question

The triangle, ABC, shown on the coordinate plane below, is dilated from the origin by a scale factor of r = 1/3. What is the location of A'B'C'?​

Answer 1

Answer:

Step-by-step explanation:

Coordinates of the vertices of the triangle ABC are A(3, 4), B(-7, 2) and C(2, 1).

Rule for the dilation of the coordinates of the ends of a segment is,

(x, y) → k(x, y)

        → (kx, ky)

Where k = scale factor by which the segment is dilated

If the given triangle ABC is dilated by a scale factor = $\frac{1}{3}$

Coordinates of the vertices of the image triangle will be,

A(3, 4) → A'(1, $\frac{4}{3}$) Or A'(1, 1.3)

B(-7, 2) → $B'(\frac{7}{3},\frac{2}{3})$ Or B'(2.3, 0.7)

C(2, 1) → $C'(\frac{2}{3},\frac{1}{3})$ Or C'(0.7, 0.3)

Now we can plot these points on the given graph