Angela and Blake are running toward each other from
15 m away. At time t = 0 s, Angela runs to the right at 5
m/s and Blake runs to the left at 3 m/s
Write an equation for Angela?

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Answer:

Kindly check explanation

Explanation:

Given the following information :

Distance between Angela and Blake = 15m

Angela's speed = 5m/s at t = 0

Angela's direction = Right = positive

Blake's speed = 3m/s at t = 0

Blake's direction = left = negative

Position or distance = speed × time

Hence,

Combined speed = (3 + 5) = 8m/s

Distance = 15m

Time = distance / speed

Time = 15 / 8

Time they meet = 1.875 seconds

Distance covered by Angela :

Speed × time

= 5 × 1.875 = 9.375 meters

The equation for the distance traveled by Angela is 5t and the distance covered by Angela  is 9.375 m.

The given parameter:

  • the distance between Angela and Blake = 15 m
  • speed of Angela, [tex]V_A[/tex] = 5 m/s
  • speed of Blake, [tex]V_B[/tex] = 3 m/s

let the time at which Angela and Blake meet = t

The equation for the distance traveled by Angela = 5t

The time (t) at which Angela and Blake meet will be calculated using relative velocity concept:

since they are closing the distance together, we will add their velocities

(i.e they are working together and not against each other)

[tex](V_A +V_B) t = 15\\\\(5 + 3) t = 15\\\\8t = 15\\\\t = \frac{15}{8} \\\\t = 1.875 \ s[/tex]

The distance covered by Angela = 1.875 s x 5 m/s = 9.375 m

The distance covered by Blake = 1.875 x 3 m/s = 5.625 m

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