Question

An isosceles right triangle whose legs are 6 is rotated about one of its legs to generate a right circular cone. What is the volume of the cone?

Answer 1

Answer:

$V = 72 \pi$

Step-by-step explanation:

The radius of the base is one of the legs, so it is 6.

The height of the cone is the other leg, so it is also 6.

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} (\pi)(6^2)(6)$

$V = (\pi)(36)(2)$

$V = 72 \pi$