Answer:
a
The charge is [tex]Q = 2.0*10^8 \ C[/tex]
b
The number of electrons [tex]N = 1.25 *10^{27} \ electrons[/tex]
Explanation:
From the question we are told that
The maximum rate of charge flow is [tex]\frac{dq}{dt} = I = 20000 \ C/s[/tex]
Here I means current
The time interval is [tex]t=100 \mu s = 100*10^{-6}[/tex]
Generally the amount of charge is mathematically represented as
[tex]Q = \frac{I}{t}[/tex]
=> [tex]Q = \frac{20000}{ 100*10^{-6}}[/tex]
=> [tex]Q = 2.0*10^8 \ C[/tex]
The number of electrons that flow during that time is evaluated as
[tex]N = \frac{Q}{e}[/tex]
Here e is the charge on a single electron with value [tex]e= 1.60*10^{-19} \ C[/tex]
So
[tex]N = \frac{2.0*10^8}{ 1.60*10^{-19}}[/tex]
[tex]N = 1.25 *10^{27} \ electrons[/tex]