Question

(x^2+4)^2−11(x^2+4)+24=0
find one solution for this equation

Answer 1

Answer:

Step-by-step explanation:

(x²+4)²-11(x²+4)+24=0

put x²+4=y

y²-11y+24=0

y²-3y-8y+24=0

y(y-3)-8(y-3)=0

(y-3)(y-8)=0

y=3,8

so x²+4=3

x²=-1=i²

x=±i

or x²+4=8

x²=4

x=±2