Respuesta :

Answer:

[tex]f^{-1}(x)=\frac{1}{6}\ln(x+9)[/tex]

Step-by-step explanation:

So we have the function:

[tex]f(x)=e^{6x}-9[/tex]

To solve for the inverse of a function, change f(x) and x, change the f(x) to f⁻¹(x), and solve for it. Therefore:

[tex]x=e^{6f^{-1}(x)}-9[/tex]

Add 9 to both sides:

[tex]x+9=e^{6f^{-1}(x)}[/tex]

Take the natural log of both sides:

[tex]\ln(x+9)=\ln(e^{6f^{-1}(x)})[/tex]

The right side cancels:

[tex]\ln(x+9)=6f^{-1}(x)[/tex]

Divide both sides by 6:

[tex]f^{-1}(x)=\frac{1}{6}\ln(x+9)[/tex]

And we're done!

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