Question

describe fully the graph which has the equation x^2+y^2=16

Answer 1

The given equation is a circle with center = (0, 0) and radius = 4.

We compare the given equation with the standard form of a circle$(x-h)^2+(y-k)^2=r^2$

So, h = 0 , k = 0, $r^2=16$ or r = 4.

So the given equation is a circle with center = (0, 0) and radius = 4.

The graph is attached.

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