Answer:
[tex]\frac{7}{15}[/tex]
Step-by-step explanation:
Given
[tex]\frac{16-4(5)}{2(6)+8}[/tex] + [tex]\frac{2}{3}[/tex]
= [tex]\frac{16-20}{12+8}[/tex] + [tex]\frac{2}{3}[/tex]
= [tex]\frac{-4}{20}[/tex] + [tex]\frac{2}{3}[/tex]
= - [tex]\frac{1}{5}[/tex] + [tex]\frac{2}{3}[/tex]
We require the fractions to have a common denominator of 15
Multiply the numerator/ denominator of - [tex]\frac{1}{5}[/tex] by 3 and
Multiply the numerator/ denominator of [tex]\frac{2}{3}[/tex] by 5
= - [tex]\frac{3}{15}[/tex] + [tex]\frac{10}{15}[/tex]
= [tex]\frac{7}{15}[/tex]
