Question

Question 2 (1 point)
Find the value of x. Round you answer to the nearest tenth.
X
16
27

Answer 1

Step-by-step explanation:

$\blue\star$By P.G.T

${h}^{2} = {b}^{2} + {p}^{2}$

${27}^{2} = {16}^{2} + {x}^{2}$

$729 = 256 + {x}^{2}$

${x }^{2} = 729 - 256$

$x = \sqrt{473}$

$\huge\boxed{x = 22}$

Hope it helps .

Answer 2

a^2=b^2+c^2.

27^2=16^2+c^2.

729=256+c^2

c^2=729-256.

c^2=√473.

c=21.74856317~21.7(to nearest tenth).