Question

Calculate the amount of heat (in kilojoules) required to vaporize 2.97 kg of water at its boiling point. (δhvap

Answer 1

$Given:\\m=2.97kg\\c_p=2,257 \frac{kJ}{kg} \\\\Find:\\Q=?\\\\Solution:\\\\Q=c_pm\\\\Q=2,257 \frac{kJ}{kg}\cdot2.97kg= 6703,29kJ$