part 7: please assist me with these problems

Answer: 10) 40° 11) 9.9
Step-by-step explanation:
[tex]\text{Law of Sines:}\quad \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}[/tex]
10) Given: a = 31, b = 20, A = 84°
[tex]\dfrac{\sin 84^o}{31}=\dfrac{\sin B}{20}\\\\\\\dfrac{20\sin 84^o}{31}=\sin B\\\\\\\sin^{-1}\bigg(\dfrac{20\sin 84^o}{31}\bigg)=B\\\\\\39.9^o=B[/tex]
11) Given: a = 18, A = 105°, B = 32°
[tex]\dfrac{\sin 105^o}{18}=\dfrac{\sin 32^o}{b}\\\\\\b=\dfrac{18\sin 32^o}{\sin 105^o}\\\\\\b=9.87[/tex]