Question

If α and β are zeroes of the polynomial q(x)=x2-7x+10, then find the value of (α+β)2-4αβ

Answer 1

Answer:

9

Step-by-step explanation:

$\alpha + \beta = -b/a = -(-7)/1 = 7$

$\alpha \beta = c/a = 10/1 = 10$

$(\alpha + \beta )^2 - 4 \alpha \beta \\ 7^2 - 4 × 10 \\ 49 - 40 \\ = 9$