If CB=2x+5 and DE=10, find the value of x

Answer:
[tex]x=4[/tex]
Step-by-step explanation:
We are given that:
[tex]CB=2x+5[/tex]
And that DE = 10. We want to determine the value of x.
Note that CB is the sum of CD and DB. In other words:
[tex]CB=CD+DB[/tex]
Similarly, DE is the sum of DB and BE. Thus:
[tex]DE=DB+BE[/tex]
From the second equation, we can subtract BE from both sides:
[tex]DE-BE=DB[/tex]
Substitute this into the first equation:
[tex]CB=CD+(DE-BE)[/tex]
We are given that CB is 2x + 5 and DE is 10.
From the diagram, we can also see that CD is 3x - 1 and BE is 8.
Substitute:
[tex](2x+5)=(3x-1)+((10)-(8))[/tex]
Solve for x:
[tex]\displaystyle \begin{aligned}(2x+5) & = (3x-1) + (2) \\ \\ 2x + 5 & = 3x + 1 \\ \\ -x + 5 & = 1 \\ \\ - x & = -4 \\ \\ x & = 4 \end{aligned}[/tex]
In conclusion, the value of x is 4.