Which function has a domain where x does not =3 and a range where y does not =2? A. f(x)=(x-5)/(x+3) B. f(x)=2(x+5)/(x+3) C. 2(x+5)/(x-3) D. (x+5)/(x-3)

Respuesta :

Answer: D. (x+5)/(x-3)

Step-by-step explanation:

Domain = Set of all input values of a function.

range = set of all output values of a function.

Given: Domain: [tex]x\neq3[/tex]   ; range = [tex]y\neq2[/tex]

We do not include a value for domain if it makes the expression indeterminant .

Since all the functions in options are fractions, here the denominator does not equal to 0.

But in option C and D, the denominator can be zero if x=3.

So , domain for then it [tex]x\in {R-3}[/tex]

Also, for option C if [tex]2=2\dfrac{(x+5)}{(x-3)}[/tex]

[tex]\Rightarrow\ x-3=x+5\\\\\Rightarrow\ -3=5[/tex].which is not true.

Wher as in option D, [tex]2=\dfrac{x+5}{x-3}\Rightarrow\ 2x-6=x+5\Rightarrow\ x=11[/tex]

Hence, Domain: [tex]x\neq3[/tex]   ; range = [tex]y\neq2[/tex] is for option D.

Answer:

OPTION D IS NOT CORRECT.

i took the test & selected D and it was wrong.

THE CORRECT ANSWER IS C.

Step-by-step explanation:

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