The graphed line shown below is y = negative 2 x minus 8. Which equation, when graphed with the given equation, will form a system that has infinitely many solutions? y = negative (2 x + 8) y = negative 2 (x minus 8) y = negative 2 (x minus 4) y = negative (negative 2 x + 8)

The graphed line shown below is y negative 2 x minus 8 Which equation when graphed with the given equation will form a system that has infinitely many solutions class=

Respuesta :

Answer: A y = -(2x+8)

Step-by-step explanation:

The first line is y=-2x-8

Thus, the answer that simplifies to y = -2x-8 is the answer.  

a) y=-(2x+8)

Distribute

y=-2x-8

Because it works, no need to try the others.

Hope it helps <3

Answer:

[tex]\boxed{y = -(2x + 8)}[/tex]

Step-by-step explanation:

For the two lines to have infinite [tex]\infty[/tex] solutions, the two equations must be the same.

First equation : y = -2x - 8

A. y = -(2x + 8)

   y = -2x - 8 correct

B. y = -2(x - 8)

   y = -2x + 16 incorrect

C. y = -2(x - 4)

   y = -2x + 8 incorrect

D. y = -(-2x+8)

    y = 2x - 8 incorrect

y = -2x - 8 and y = -(2x + 8) when graphed are the same, they intersect at infinite points and there are infinite solutions.

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