Question

The x-intercepts of a parabola are (-5, 0) and (3, 0). What is the function of the parabola?
ỌA 1x) = -2(x+2x-5)
OB. x) = -2(x²+2x-15)
OC. Rx) = -2(x²-2x-15)
OD. x) = -2(x²-2x-5)

Answer 1

The function of the parabola will be f(x) =  -2(x²+2x-15)

Equation of a parabola

The equation of a parabola are quadratic in nature.

If s graph has intercepts (a, 0) and (b, 0), the function will be equivalent to;

f(x) = (x-a)(x-b)

Since we are given the x-intercepts (-5, 0) and (3, 0), the function of the parabola will be:

f(x) = (x+5)(x-3)

Expand

f(x) = x^2 - 3x + 5x - 15

f(x) = x^2 + 2x - 15

Hence the function of the parabola will be f(x) =  -2(x²+2x-15)

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