Question

Help! please very urgent Segment AB has point A located at (8, 9). If the distance from A to B is 10 units, which of the following could be used to calculate the coordinates for point B

10 = square root of the quantity of x plus 8 all squared plus y plus 9 all squared
10 = square root of the quantity of x plus 9 all squared plus y plus 8 all squared
10 = square root of the quantity of x minus 8 all squared plus y minus 9 all squared
10 = square root of the quantity of x minus 9 all squared plus y minus 8 all squared

Answer 1

Answer:

the third one

Step-by-step explanation:

We have A(8.9) and B(x,y)

so vector AB(x-8,y-9)

Then :

10= $\sqrt{(x-8)^{2}+(y-9)^{2} }$

Answer 2

10 = square root[quantity of x minus 8 all squared + y minus 9 all squared]

So,

Option "C" is the correct answer to the following question.

Step-by-step explanation:

Given:

Distance of segment AB = 10 Unit

Coordination of A = (8 , 9)

Find;

Equation to find Coordination of B

Computation:

Distance of segment = $\sqrt{(x1 - x2)^2 + (y1 - y2)^2}$

So,

$10 = \sqrt{(x - 8)^2 + (y - 9^2)}$

Or

10 = square root[quantity of x minus 8 all squared + y minus 9 all squared]

Learn more:

https://brainly.com/question/23782800?referrer=searchResults