Answer:
a.[tex]2.86 m/s^2[/tex]
b.1058 N
Explanation:
We are given that
Mass of each dog,M=18.5 kg
Mass of sled with rider,m=250 kg
a.Average force,F=185 N
[tex]\mu_s=0.14[/tex]
[tex]g=9.8 m/s^2[/tex]
By Newton's second law
[tex]8F-f=(8M+m)a[/tex]
[tex]a=\frac{8F-f}{8M+m}=\frac{8(185)-(0.14)(9.8)(250)}{8(18.5)+250}[/tex]
[tex]a=2.86 m/s^2[/tex]
b.By Newton's second law
[tex]T=ma+\mu_s mg[/tex]
Substitute the values
[tex]T=250\times 2.86+0.14(250)(9.8)=1058 N[/tex]
Hence, the force in the coupling between the dogs and the sled=1058 N