Question

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. What is the magnitude of an earthquake that is 1,000 times more intense than a standard earthquake? Use a calculator. Round your answer to the nearest tenth.

Answer 1

Answer:

3.0

Step-by-step explanation:

The magnitude of an earthquake is given as:

$M = log_{10}\frac{I}{S}$

where I = intensity of earthquake

S = intensity of standard earth quake

When the intensity of the earthquake is 1000 times the intensity of a standard earth, that means that:

I = 1000S

Therefore:

$M = log_{10}\frac{1000S}{S} \\\\M = log_{10}1000\\\\M = 3.0$

The magnitude is 3.0

Answer 2

Answer: it’s B on edge

Step-by-step explanation: