Answer:
[tex] \boxed{\sf (b) \ x = -3} [/tex]
Step-by-step explanation:
[tex] \sf Solve \: for \: x: \\ \sf \implies 3 - 2x = 9 \\ \\ \sf Subtract \: 3 \: from \: both \: sides: \\ \sf \implies (3 - \boxed{3}) - 2x = 9 - \boxed{3} \\ \\ \sf 3 - 3 = 0 : \\ \sf \implies - 2x = 9 - 3 \\ \\ \sf 9 - 3 = 6 : \\ \sf \implies - 2x = \boxed{6} \\ \\ \sf Divide \: both \: sides \: of \: - 2 x = 6 \: by \: - 2: \\ \sf \implies \frac{ - 2 x}{ - 2} = \frac{6}{ - 2} \\ \\ \sf \frac{ - 2}{ - 2} = 1 : \\ \sf \implies x = - \frac{6}{2} \\ \\ \sf \implies x = - \frac{3 \times \cancel{2}}{ \cancel{2}} \\ \\ \sf \implies x = - 3[/tex]
