The compound with molar mass 28 g/mol has been ethylene, with the molecular formula [tex]\rm \bold{C_2H_4}[/tex].
The Lewis structure has been the structure of the molecule consisting of the number of bonds present in the compound. The given compound has been 100% weight/weight.
The percent of carbon = 85.7%
The percent of hydrogen = 14.3%
The compound has molecular mass = 28 g/mol
Since, the given percent of hydrogen and carbon has been weight %. The mass of hydrogen and carbon has been:
Mass of carbon = 85.7 g
Mass of hydrogen = 14.3 g
The moles of hydrogen and carbon in the compound has been:
[tex]\rm Moles\;=\;\dfrac{Mass}{Molecular\;mass}[/tex]
Moles of carbon can be given as:
[tex]\rm Moles\;of\;carbon\;=\;\dfrac{85.7\;g}{12.01\;g/mol}[/tex]
Moles of carbon = 7.13 mol
Moles of hydrogen can be given as:
[tex]\rm Moles\;of\;hydrogen\;=\;\dfrac{14.3\;g}{1.008\;g/mol}[/tex]
Moles of hydrogen = 14.19 mol
In the given molecular compound, the number of atoms of hydrogen and carbon has been calculated with respect to carbon moles, to give the empirical formula of the compound.
The atoms of carbon has been:
[tex]\rm Carbon\;=\;\dfrac{7.13}{7.13}[/tex]
Carbon = 1
The atoms of hydrogen has been:
[tex]\rm Hydrogen\;=\;\dfrac{14.19}{7.13}[/tex]
Hydrogen = 2
The empirical formula of compound has been [tex]\rm \bold{CH_2}[/tex].
The compound has molar mass 28 g/mol.
The mass of [tex]\rm \bold{CH_2}[/tex] = 14 g/mol
The number of empirical formula unit has been given as:
[tex]\rm Number\;of\;empirical\;formula\;unit\;=\;\dfrac{14}{28}[/tex]
Number of empirical formula unit = 2
Thus the molecular formula of the compound has been [tex]\rm \bold{C_2H_4}[/tex]. The attached image has been the structure of ethylene.
The compound with molar mass 28 g/mol has been ethylene, with the molecular formula [tex]\rm \bold{C_2H_4}[/tex].
For more information about the Lewis structure, refer to the link:
https://brainly.com/question/4144781
