Answer:
3.6% of the ball bearings will have diameters of 20.27 mm or more.
Step-by-step explanation:
We can calculate this proportion using the z-score.
We have a normal distribution with mean 20.00 mm and standard deviation of 0.150 mm.
The value for X is 20.27 mm.
Then, the z-score and its associated probability are:
[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{20.27-20}{0.15}=\dfrac{0.27}{0.15}=1.8\\\\\\P(X>20.27)=P(z>1.8)=0.036=3.6\%[/tex]