Since the roads are perpendicular to each other. And for perpendicular lines, product of slopes is equal to -1 .
So for the first car , with the points , (-3,2),(1,-2), slope is
[tex]m_{1} = \frac{-2-2}{1-(-3)} = \frac{-4}{4} = -1[/tex]
And for the second car, with points (-1,-2),(3,y), slope is
[tex]m_{2} = \frac{y-(-2)}{3-(-1)} = \frac{y+2}{4}[/tex]
And product of slopes have to be -1, that is
[tex]m_{1}*m_{2} =-1[/tex]
Substituting the values of the two slopes
[tex]=> -1* \frac{y+2}{4} =-1 \\ =>\frac{y+2}{4} =1[/tex]
Multiplying both sides by 4
[tex]y+2 =4 \\ y=4-2 \\ y=2[/tex]
And that's the missing value of y coordinate .