Question

Sulfur reacts with oxygen to form sulfur dioxide (SO2(g), Delta.Hf = –296.8 kJ/mol) according to the equation below. Upper S (s) plus upper O subscript 2 (g) right arrow upper S upper o subscript 2 (g). What is the enthalpy change for the reaction? Use Delta H r x n equals the sum of delta H f of all the products minus the sum of delta H f of all the reactants..

Answer 1

Answer:

$-148400$

Explanation:

$2g \times n = - 296.8 kj\\ 2g = 0.002k \\ 0.002k \times n = - 296.8 kj\\ n = - 296.8 kj \div 0.002k \\ n = - 148400$

Answer 2

Answer:

B

Explanation:

Just took the test :D