Respuesta :
5x^2 - 4x = 6
5x^2 - 4x - 6 = 0
Use the quadratic equation (I attached a photo of it)
Now, you can use this formula to know what to plug into the formula:
ax^2 + bx + c = 0
The easiest way to understand what to plug in is just to put your equation right next to this one:
ax^2 + bx + c = 0
5x^2 - 4x - 6 = 0
So,
A= 5
B= -4
C= -6
So, plug it in a solve. Remember you cannot take the square root of a negative number or 0. If it does not come to a number that is easily square rooted you must simplify it to this for example: 5 times the square root of 7. Also, your answer will be x plus or minus a number. This means that the number could be either negative or positive. If you have anymore questions let me know.
5x^2 - 4x - 6 = 0
Use the quadratic equation (I attached a photo of it)
Now, you can use this formula to know what to plug into the formula:
ax^2 + bx + c = 0
The easiest way to understand what to plug in is just to put your equation right next to this one:
ax^2 + bx + c = 0
5x^2 - 4x - 6 = 0
So,
A= 5
B= -4
C= -6
So, plug it in a solve. Remember you cannot take the square root of a negative number or 0. If it does not come to a number that is easily square rooted you must simplify it to this for example: 5 times the square root of 7. Also, your answer will be x plus or minus a number. This means that the number could be either negative or positive. If you have anymore questions let me know.
Answer:
[tex]x=\frac{2+\sqrt{34}}{5}[/tex] and [tex]x=\frac{2-\sqrt{34}}{5}[/tex]
Step-by-step explanation:
[tex]5x^2-4x=6[/tex]
To solve for x , we need to get 0 on the right side
Subtract 6 on both sides
[tex]5x^2-4x-6=0[/tex]
Factor the left hand side
To solve for x , we apply quadratic formula
[tex]x=\frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]
The value of a=5, b=-4, c= -6
[tex]x=\frac{4+-\sqrt{(-4)^2-4(5)(-6)}}{2(5)}[/tex]
[tex]x=\frac{4+-\sqrt{136}}{10}[/tex]
[tex]x=\frac{4+-2\sqrt{34}}{10}[/tex]
Divide top and bottom by 2
[tex]x=\frac{2+-\sqrt{34}}{5}[/tex]