Molarity problem:
Assuming the density of vinegar is 1.0 g/mL, what is the molarity of vinegar? (Use the percent by mass of acetic acid in vinegar from question 1 which is 5.3%). The molar mass of acetic acid is 60.05 g/mol.
There are a number of ways
to express concentration of a solution. This includes molarity. Molarity is
expressed as the number of moles of solute per volume of the solution.
5.3 % = 5.3 g acetic acid / 100 g solution
Molarity = 5.3 g acetic acid / 100 g solution ( 1.0 g solution / .001 L solution ) ( 1 mol acetic acid/ 60.05 g acetic acid ) = 0.8826 mol / L solution