Question

Determine the chemical amount of chlorine required to produce 2.50 mol of lithium chloride, LiCl, according to the equation Select one: a. 1.50 mol b. 2.00 mol c. 1.25 mol d. 1.75 mol

Answer 1

Answer:

c. 1.25 mol

Explanation:

You might find it helpful to sort the information under the equation like a chart. "n" is the symbol for moles.

        2 LiI(aq) + Cl₂(aq) → 2 LiCl(aq) + I₂(s)

n                           ?           2.50 mol

We are looking for the chemical amount of chlorine, or moles of chlorine.

To find the number of moles, you need the mole ratio.

The mole ratio is the same as the coefficients in the equation.

   Cl₂ to LiCl

1 mol to 2 mol

Start with the given moles (2.50 mol for LiCl) and multiply by the mole ratio.

Since we are looking for molCl₂, write molCl₂ on top.

$n_{Cl_{2}} = 2.50 mol_{LiCl} * \frac{1mol_{Cl_{2}}}{2 mol_{LiCl}}$            Units for molLiCl cancel out

$n_{Cl_{2}} = 1.25 mol_{Cl_{2}}$          <= notice that we keep 3 significant figures

The chemical amount of chlorine is 1.25 mol.