Respuesta :
we are given the reaction Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag. This means for every mole Cu used, there are 2 moles of Ag produced. In this case, given 31.75 g Cu, converting to moles through molar mass and using stoichiometric ratio and the molar mass of Ag, the mass Ag produced is 107.9 grams.
The mass in grams of Ag produced from reaction of 31.75g of Cu is 107.9 grams
calculation
Cu+2AgNO3 ---> Cu(NO3)2 + 2Ag
find the moles of Cu that reacted
moles= mass/molar mass
=31.75 g/63.5 g/mol= 0.5 moles
from the equation above the mole ratio of CU:Ag is 1:2 therefore the moles of Ag=0.5 moles x2 = 1 mole
mass of Ag= moles of Ag x molar mass
= 1 mole x107.9g/mol = 107.9 grams